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karolisk

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get parent node with YUI3 by selector

Post Posted: Wed Jun 20, 2012 11:01 pm
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Hi all,

I have a very simple question for which I cannot find answer in documentation - how to get parent node by selector. I found only one without selector.
[node].get('parentNode')

And if there is such functionality I wonder if it's documented.

thanks

Juan Ignacio Dopazo

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Re: get parent node with YUI3 by selector

Post Posted: Thu Jun 21, 2012 4:55 am
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Hey!

I don't think there's a NodeList method for parents, but you can filter the parent nodes by doing nodeList.get('parentNode').filter(selector).

Todd Smith

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Re: get parent node with YUI3 by selector

Post Posted: Thu Jun 21, 2012 6:04 am
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Also from a Node, you can call the Node ancestor method. Without any selector it returns the parent. When used with a selector it returns the closest matching selector.

Code:
<div id="A">
   <span id="B">
        <ol id="C">
           <li id="D">List 1</li>
           <li>List 2</li>
        </ol>
   </span>
</div>

Y.one("#D").ancestor();   // returns the OL #C
Y.one("#D").ancestor().ancestor();   // returns SPAN #B
Y.one("#D").ancestor("span");   // also returns SPAN #B
Y.one("#D").ancestor("div");   // returns DIV #A

karolisk

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Re: get parent node with YUI3 by selector

Post Posted: Fri Jun 22, 2012 4:17 am
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It is exactly what I'm looking for, thanks!
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